Comments on Two MLM cats mate. What is the probability that any one of their surviving kittens will be heterozygous?
January 27, 2009
Weird Fishes @ 1:19 pm
So MLM x MLM, your possible outcomes are:
1 MLML - Die before birth
2 MLM - Manx
or 1 MM - Normal
Since MLML dies before birth, you change the ratio to 2/3 MLM and 1/3 Normal, therefore 2 out of every 3 *surviving* kittens will be heterozygotes, and 1 will be normal.
Comments on Two MLM cats mate. What is the probability that any one of their surviving kittens will be heterozygous?
So MLM x MLM, your possible outcomes are:
1 MLML - Die before birth
2 MLM - Manx
or 1 MM - Normal
Since MLML dies before birth, you change the ratio to 2/3 MLM and 1/3 Normal, therefore 2 out of every 3 *surviving* kittens will be heterozygotes, and 1 will be normal.